A group of naturalists catch, tag and release 121 trout into a lake. The next day they catch and release 48 trout, of which 22 had been tagged. Using this ratio, how many trout would be estimated to be in the lake?

We have been given that a group of naturalists catch, tag and release 121 trout into a lake. The next day they catch and release 48 trout, of which 22 had been tagged.

Using proportions, we will get:

[tex]\frac{\text{Total trouts}}{\text{Tagged trouts}}=\frac{48}{22}[/tex]

[tex]\frac{x}{121}=\frac{48}{22}[/tex]

[tex]\frac{x}{121}*121=\frac{48}{22}*121[/tex]

[tex]x=\frac{24}{11}*121[/tex]

[tex]x=24*11[/tex]

[tex]x=264[/tex]

Therefore, there would be approximately 264 trout in the lake.

lachellecagil lachellecagil · Answer 2 · 2020-07-10T07:00:06+02:00

lachellecagil lachellecagil

10-07-2020

264 trouts are estimated to be in the lake.

Using proportion, we write: Tagged trout/Total Trout

This becomes 22/48.

In order to use cross multiplication, we write another fraction using x, the total number of trout in the lake: 121/x.

Now we have 121/x=22/48.

We cross multiply.

121*48=22x.

(121*48)/22 becomes:

264.

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