Respuesta :
Answer: The boiling point of an benzene solution is [tex]82.57^0C[/tex]
Explanation:
Depression in freezing point is given by:
[tex]\Delta T_f=i\times K_f\times m[/tex]
[tex]\Delta T_f=T_f^0-T_f=(5.5-0.3)^0C=5.2^0C=5.2K[/tex] = Depression in freezing point
i= vant hoff factor = 1 (for non electrolyte)
[tex]K_f[/tex] = freezing point constant = [tex]5.12K/m[/tex]
m= molality
[tex]5.2=1\times 5.12\times m[/tex]
[tex]m=1.015[/tex]
Elevation in boiling point is given by:
[tex]\Delta T_b=i\times K_b\times m[/tex]
[tex]\Delta T_b=Tb-Tb^0=(Tb-80.1)^0C[/tex] = elevation in boiling point
i= vant hoff factor = 1 (for non electrolyte)
[tex]K_b[/tex] = boiling point constant = [tex]2.43K/m[/tex]
m= molality = 1.015
[tex](T_b-80.1)^0C=1\times 2.43\times 1.015[/tex]
[tex]T_b=82.57^0C[/tex]
Thus the boiling point of an benzene solution is [tex]82.57^0C[/tex]
