contestada

A hockey puck is struck so that it slides at a constant speed and strikes the far side of the rink, 58.2 m away. The shooter hears the sound of the puck after 1.9 seconds. The speed of sound is 340 m/s.

How fast was the puck moving?

Respuesta :

Answer:

[tex]v = 33.66 m/s[/tex]

Explanation:

Let hockey puck is moving at constant speed v

so here we have

[tex]d = vt[/tex]

so time taken by the puck to strike the wall is given as

[tex]t = \frac{58.2}{v}[/tex]

now time taken by sound to come back at the position of shooter is given as

[tex]t_2 = \frac{58.2}{340}[/tex]

[tex]t_2 = 0.17s[/tex]

so we know that total time is 1.9 s

[tex]1.9 = t + t_2[/tex]

[tex]1.9 = t + 0.17[/tex]

[tex]1.9 - 0.17 = t[/tex]

[tex]t = 1.73 s[/tex]

now we have

[tex]1.73 = \frac{58.2}{v}[/tex]

[tex]v = 33.66 m/s[/tex]

Otras preguntas