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an 1.04-L sample of gas at 759 mm Hg pressure
expanded until its volume is 2.24 L. What
the pressure in the expanded gas sample
at constant temperature)?

Respuesta :

corispastries

PV = nRT

where P is the pressure,

V is the volume,

n is the moles of gas,

R is the gas constant,

and T is the temperature.

We must relate this equation to a sample of gas at two different volumes however. Looking at the equation, we can relate the change in volume by:

P1V1 = P2V2

where P1 is the initial pressure,

V1 is the initial volume,

P2 is the final pressure,

and V2 is the final volume.

Looking at this relationship, pressure and volume have an indirect relationship; when one goes up, the other goes down. In that case, we can use this equation to solve for the new pressure.

P1V1 = P2V2

(759 mm Hg)(1.04 L) = P2(2.24 L)

P2 = 352 mm Hg (rounded to three significant figures)

samueladesida43

The pressure of the expanded gas sample at a constant temperature is 352.4mmHg

HOW TO CALCULATE PRESSURE:

  • The new pressure of a gas can be calculated using Boyle's law formula as follows:

  • P1V1 = P2V2

Where;

  1. P1 = initial pressure (mmHg)
  2. P2 = final pressure (mmHg)
  3. V1 = initial volume (L)
  4. V2 = final volume (L)

  • According to this question;
  1. P1 = 759 mmHg
  2. P2 = ?
  3. V1 = 1.04L
  4. V2 = 2.24 L

759 × 1.04 = P2 × 2.24

789.36 = 2.24P2

P2 = 789.36 ÷ 2.24

P2 = 352.4mmHg

  • Therefore, the pressure of the expanded gas sample at a constant temperature is 352.4mmHg.

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