Respuesta :
Answer:
0.961
Explanation:
m1 = 300 g = 0.3 kg
u1 = 1 m/s
m2 = 600 g = 0.6 kg
u2 = - 0.75 m/s
Let after collision they move together with velocity v.
By using the conservation of linear momentum
Total momentum before collision = Total momentum after collision
m1 x u1 + m2 x u2 = (m1 + m2) v
0.3 x 1 - 0.6 x 0.75 = (0.3 + 0.6) v
0.3 - 0.45 = 0.9 v
v = - 0.166 m/s
Total initial Kinetic energy
[tex]K_{i}=0.5m_{1}u_{1}^{2}+0.5m_{1}u_{1}^{2}[/tex]
[tex]K_{i}=0.5\times 0.3\times 1\times 1+0.5 \times 0.6 \times 0.75 \times 0.75[/tex]
[tex]K_{i}=0.31875 J[/tex]
Total final Kinetic energy
[tex]K_{f}=0.5\left ( m_{1}+m_{2} \right )v^{2}[/tex]
[tex]K_{f}=0.5\times 0.9 \times 0.166 \times 0.166[/tex]
[tex]K_{f}=0.0124 J[/tex]
fraction of kinetic energy lost
[tex]\frac{K_{i}-K_{f}}{K_{f}}=\frac{0.31875-0.0124}{0.31875}=0.961[/tex]
Two pieces of clay are moves directly, and collide the momentum before and after the collision remain same. The fraction part of the total initial kinetic energy lost during the collision is 0.961.
What is kinetic energy?
Kinetic energy is the energy of of the body, which it posses due to force of motion. The kinetic energy of a body is half of the product of mass times square of its velocity.
Given information-
The mass of piece one is 300 grams.
The mass of the second piece is 600 grams.
The speed of the first piece is 1 m/s.
The speed of the second piece is 0.75 m/s.
By the conservation of momentum, we know that the momentum of two body before the collision is equal to the momentum after the collision. As the momentum is product of mass times velocity. Thus,
[tex]m_1v_1+m_2v_2=(m_1+m_2)v[/tex]
Here, [tex]m_1,m_2[/tex] is the mass of body one, body 2 respectively and [tex]v_1,v_2[/tex] are the velocities of body one, body two before the collision respectively.
Put the values to find the value of velocity after the collision as,
[tex]0.3\times1+0.6\times0.75=(0.3+0.6)v\\v=-0.166 m/s[/tex]
Negative sine indicates the direction after the collision is changed.
Now the kinetic energy lost is the ratio of difference of initial kinetic energy and final kinetic energy to the initial kinetic energy.
Thus the kinetic energy lost is,
[tex]\Delta KE=\dfrac{k_i-k_f}{k_f}[/tex]
The kinetic energy is the half of the mass time square of its velocity. Thus,
[tex]\Delta KE=\dfrac{(\dfrac{1}{2}0.3\times0.1^2)-(\dfrac{1}{2}0.6\times0.75^2)}{\dfrac{1}{2}0.3\times0.1^2}\\\Delta KE=0.961[/tex]
Thus the fraction part of the total initial kinetic energy lost during the collision is 0.961.
Learn more about the collision here;
https://brainly.com/question/7694106
