Respuesta :
Explanation:
Since, it is known that number of moles equal to the mass divided by the molar mass of a substance.
As molar mass of NaCl is 58.44 g/mol. Hence, number of moles of NaCl present in 158.84 g are calculated as follows.
No. of moles = [tex]\frac{mass}{\text{molar mass}}[/tex]
= [tex]\frac{158.84 g}{58.44 g/mol}[/tex]
= 2.715 mol
Therefore, there are 2.715 moles present in 100 ml solvent.
Hence, the molar concentration will be as follows.
Molar concentration = [tex]\frac{2.715 mol}{100 \times 10^{-3}}[/tex] mol/liter
= 27.15 M
It is given that error in weight is 0.005 g and error in volume is 0.2 ml.
Hence, total volume will be (100ml + 0.2 ml) = 100.2 ml.
Therefore, now molar concentration will be as follows.
Molar concentration = [tex]\frac{2.715 mol}{100.2 \times 10^{-3}}[/tex] mol/liter
= 27.09 M
Thus, calculate the deviation as follows.
(27.15 - 27.09) mol/liter
= 0.06 mol/liter
Hence, we can conclude that the molar concentration of sodium chloride 27.15 M and its associated standard deviation is 0.06 mol/liter.
