Respuesta :
Explanation:
The given precipitation reaction will be as follows.
[tex]AgNO_{3}(aq) + NaCl(aq) \rightarrow AgCl(s) + NaNO_{3}(aq)[/tex]
Here, AgCl is the precipitate which is formed.
It is known that molarity is the number of moles present in a liter of solution.
Mathematically, Molarity = [tex]\frac{\text{no. of moles}}{\text{volume in liter}}[/tex]
It is given that volume is 1.14 L and molarity is 0.269 M. Therefore, calculate number of moles as follows.
Molarity = [tex]\frac{\text{no. of moles}}{\text{volume in liter}}[/tex]
0.269 M = [tex]\frac{\text{no. of moles}}{1.14 L}[/tex]
no. of moles = 0.306 mol
As molar mass of AgCl is 143.32 g/mol. Also, relation between number of moles and mass is as follows.
No. of moles = [tex]\frac{mass}{\text{molar mass}}[/tex]
0.307 mol = [tex]\frac{mass}{143.32 g/mol}[/tex]
mass = 43.99 g
Thus, we can conclude that mass of precipitate produced is 43.99 g.
