Answer:
216.97 X 10⁻⁵ N
Explanation:
Charge q₁ and q₂ will attract q₃ with force F₁ and F₂ .F₁ and F₂ will be calculated as follows
F₁ = [tex]\frac{9\times10^9\times8\times7.7\times10^{-18}}{(2.6\times10^{-2})^2}[/tex]
F₁ = 82.01 X 10⁻⁵ N
F₂= [tex]\frac{9\times10^9\times8\times15.4\times10^{-18}}{(2.6\times10^{-2})^2}[/tex]
F₂ = 164.02 X 10⁻⁵ N
F₁ and F₂ will act at 60 degree so their resultant will be calculated as follows
R² = (82.01 X 10⁻⁵)² +( 164.02 X 10⁻⁵ )² + 2 X 82.01 X 164.02 X 10⁻¹⁰ Cos 60
R² = 47079.48 X 10⁻¹⁰
R = 216.97 X 10⁻⁵ N
