Answer:
1.81 x 10^-4 m/s
Explanation:
M = 98700 kg
m = 780 kg
d = 201 m
Let the speed of second asteroid is v.
The gravitational force between the two asteroids is balanced by the centripetal force on the second asteroid.
[tex]\frac{GMm}{d^{2}}=\frac{mv^2}{d}[/tex]
[tex]v=\sqrt{\frac{GM}{d}}[/tex]
Where, G be the universal gravitational constant.
G = 6.67 x 10^-11 Nm^2/kg^2
[tex]v=\sqrt{\frac{6.67 \times 10^{-11}\times 98700}{201}}[/tex]
v = 1.81 x 10^-4 m/s
