Answer:
[tex]524.5903\mu m^{3}[/tex]
Explanation:
Given that, consider the model of a cell as a sphere.
The size of the human cell is [tex]10\mu m[/tex].
And its radius will become [tex]r_{c}=\frac{10\mu m}{2} =5\mu m[/tex]
And the size of the membrane is [tex]4 nm[/tex].
Now the radius of the cell with the membrane is,
[tex]r=r_{c}+r_{m}\\r=5\mu m+4nm\\r=5\mu m+0.004\mu m\\r=5.004\mu m[/tex]
Now volume with the membrane will be,
[tex]V=\frac{4}{3}\pi r^{3} \\V=\frac{4}{3}\pi (5.004)^{3}\\V=\frac{4}{3}\pi\times 125.30024\\V=524.5903\mu m^{3}\\[/tex]
This is the required volume of cell with the membrane.
