Answer:
a) 0.2399 mi³
b) 440.8 × 10³ Pounds
Explanation:
Given:
Volume of cumulus cloud, V = 1 km³
Liquid water content = 0.2 g/m³
Now,
a) 1 km = [tex]\frac{\textup{1 miles}}{\textup{1.6093}}[/tex]
thus,
1 km³ = [tex](\frac{\textup{1 miles}}{\textup{1.6093}})^3[/tex]
1 km³ = 0.2399 mi³
Hence, volume of cloud in cubic miles is 0.2399 mi³
b)
Liquid water content = 0.2 g/m³
Now,
1 Km = 1000 m
thus,
1 km³ = 1000³ m³
Therefore,
Liquid water content in 1 Km³ of cloud = 0.2 g/m³ × 1000³ m³
= 200 × 10⁶ gram
or
= 200 × 10³ Kg
also,
1 kilogram = 2.204 pounds
Therefore,
200 × 10³ Kg = 200 × 10³ × 2.204 pounds = 440.8 × 10³ Pounds