Answer:
1.3 × 10⁸ e⁻
Explanation:
When a honeybee flies through the air, it develops a charge of +20 pC = + 20 × 10⁻¹² C. This is a consequence of losing electrons (negative charges). The charge of 1 mole of electrons is 96468 C (Faraday's constant). The moles of electrons representing 20 pC are:
20 × 10⁻¹² C × (1 mol e⁻/ 96468 C) = 2.1 × 10⁻¹⁶ mol e⁻
1 mole of electrons has 6.02 × 10²³ electrons (Avogadro's number). The electrons is 2.1 × 10⁻¹⁶ moles of electrons are:
2.1 × 10⁻¹⁶ mol e⁻ × (6.02 × 10²³ e⁻/ 1 mol e⁻) = 1.3 × 10⁸ e⁻
The number of electrons lost by the by the honeybee in acquiring the charge of +20 pC is;
n = 1.25 × 10^(8) electrons
We are given;
Charge of honeybee; Q = 20 pC = 20 × 10^(-12) C
Now, formula for number of electrons is;
n = Q/e
Where;
e is charge on electron = 1.6 × 10^(-19) C
Thus;
n = (20 × 10^(-12))/(1.6 × 10^(-19))
n = 1.25 × 10^(8) electrons
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