Answer:
The magnitude of the current circulating through the coil is 1.68 mA.
Explanation:
Given that,
Number of turns = 100
Length = 5 cm
Resistance = 12.0 Ω
Rate of magnetic field = 0.081 T/s
We need to calculate the magnitude of the current circulating through the coil
Using formula of current
[tex]I=\dfrac{e}{R}[/tex]
[tex]I=\dfrac{-NA\dfrac{dB}{dt}}{R}[/tex]
Where, A = area
N = number of turns
R = resistance
Put the value into the formula
[tex]I=\dfrac{100\times(0.05)^2\times0.081}{12.0}[/tex]
[tex]I=0.0016875\ A[/tex]
[tex]I=1.68\times10^{-3}\ A[/tex]
[tex]I=1.68\ mA[/tex]
Hence, The magnitude of the current circulating through the coil is 1.68 mA.
