Answer:
The domain of f(x) = √[(1/3)x +2] is [-6, ∞).
Step-by-step explanation:
GIven f(x) = √[(1/3)x +2], you have to find the values for which the the expression inseide the square will be possitive (for negative values the function is not defined for Reals.
(1/3)x + 2 = 0 ⇒ (1/3)x = -2 ⇒ x = -2/(1/3) ⇒ x = -6
Finally the domain of f(x) is (-6, ∞).
