Answer:
h₂ = 27.22m : height the pellet reaches
Explanation:
Pellet kinetics
Pellet moves with uniformly accelerated movement in
freefall
v f₁²=v₀²+2g*h₁ (formula 1) : ball movement down
v f₂²=v₀²-2g*h₂ (formula (formula 2) : ball movement up
d:displacement in meters (m)
v₀: initial speed in m/s
vf: final speed in m/s
g: acceleration due to gravity in m/s²
h :height in m
Known data
g=9.8 m/s²
h₁=12.7m
v f₁= 27.9 m/s
Initial velocity calculation (v₀)
We replace the data in formula 1:
27.9²=v₀²+2*9.8* 12.7
27.9²-2*9.8* 12.7=v₀²
529.49=v₀²
[tex]v_{o} =\sqrt{529.49}[/tex]
[tex]v_{o} =23.1\frac{m}{s}[/tex]
Calculation of the height that the pellet reaches when it goes up
Data:
[tex]v_{o} =23.1\frac{m}{s}[/tex]
v f₂=0 :When the pellet reaches the maximum height the final speed is zero
We replace the data in formula (2)
0²=23.1²-2*9.8*h₂
19.6h₂ =23.1²
h₂ =23.1²÷19.6
h₂ =27.22m
