Answer:
90°
Explanation:
the formula for the maximum height is given by
[tex]H = \frac{v_{i}^{2}Sin^{2}\theta }{2g}[/tex]
where, vi be the initial speed with which the ball if projected, θθis the angle of projection, g be the value of acceleration due to gravity.
To get the maximum value of height, the angle of projection should be maximum,
The maximum value of Sine function is 1. So,
Sinθ = 1
θ = 90°
Thus, the height is maximum when the angle of projection is 90°.