Respuesta :

joseaaronlara

Answer:

The answer to your question is: 9.085 x 10 ⁻⁵ mg

Explanation:

Data

1.6×1017 sucrose (C12H22O11) molecules.

MW sucrose = (12x12) + ((1x22) + (16x11) = 144 + 22 + 176 = 342 mg

To solve it we use rule of three

            1 mol ---------------------- 6.023 x 10²³ molecules

              x     -----------------------    1.6 x 10¹⁷ molecules

x = 1.6 x 10¹⁷ x 1 /6.023 x 10²³

x = 2.656 x 10⁻⁷ moles

             342 mg -----------------  1 mol

               x ------------------------- 2.656 x 10⁻⁷ moles

x = 2.656 x 10⁻⁷ moles x 342/1 = 9.085 x 10⁻⁵ mg

Eduard22sly

The mass (in mg) of 1.6×10¹⁷ molecules of sucrose, C₁₂H₂₂O₁₁ is 9.09×10¯² mg

From Avogadro's hypothesis,

6.02×10²³ molecules = 1 mole of any substance

Thus,

6.02×10²³ molecules = 1 mole of C₁₂H₂₂O₁₁

Recall,

1 mole of C₁₂H₂₂O₁₁ = (12×12) + (1×22) + (16×11)

= 144 + 22 + 176

= 342 g

Next, we shall convert 342 g to mg. This can be obtained as follow

1 g = 1000 mg

Therefore,

342 g = 342 × 1000

342 g = 342000 mg

  • Therefore, we can say that:

6.02×10²³ molecules = 342000 mg of C₁₂H₂₂O₁₁

  • Finally, we shall determine the mass (in mg) of 1.6×10¹⁷ molecules of C₁₂H₂₂O₁₁. This can be obtained as follow:

6.02×10²³ molecules = 342000 mg of C₁₂H₂₂O₁₁

Therefore,

1.6×10¹⁷ molecules =  [tex]\frac{1.6X10^{17} X342000}{6.02X10^{23} }[/tex]

1.6×10¹⁷ molecules = 9.09×10¯² mg

Therefore, the mass (in mg) of 1.6×10¹⁷ molecules of sucrose, C₁₂H₂₂O₁₁ is 9.09×10¯² mg

Learn more: https://brainly.com/question/24758872

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