Respuesta :
Answer:
the final pressure = 1120 torr
Explanation:
In the starting, when a 10-L drum consist 6 L of ether at 18°C
Volume of gas [tex]= ( 10 L - 6 L ) = 4 L[/tex]
Total pressure of gas which is equal to Atmospheric Pressure = 760 Torr
vapor pressure of liquid (ether) = 400 Torr
vapor pressure of air
[tex] = ( 760 Torr - 400 Torr ) = 360 Torr[/tex]
when the drum top is sealed & dented to 8 L capacity
Volume of gas [tex] = ( 8 L - 6 L ) = 2 L[/tex]
Total pressure of gasses
[tex] = 760 Torr x ( 4 L / 2 L ) = 1560 Torr[/tex]
vapor pressure of ether [tex]= 400 Torr x 2 = 800 Torr[/tex]
vapor pressure of air [tex]= 360 Torr x 2 = 720 Torr[/tex]
But some of the liquid (ether) vapor will condensed into liquid just to maintain the vapor pressure of ether at 400 Torr )
therefore, the final pressure
[tex]= [ 400\ Torr (ether ) + 720\ Torr (air) ] = 1120 Torr[/tex]
Answer:
final total pressure is 1120 torr
Explanation:
given data
volume v1 = 10 L
volume v2 = 6 L
temperature = 18°C
atmosphere pressure P = 760 torr
volume v3 = 8 L
vapor pressure = 400 torr
to find out
pressure inside the dented
solution
we know here at 6 L volume by small amount of vaporize no temperature will change
and
gas volume in drum is = 10 - 6 = 4L
and
atmosphere pressure = total pressure inside drum
and
partial pressure of air is = 760 - 400
partial pressure of air is = 360 torr
so
at 8 L volume sealed and sealed then gas volume inside drum is
gas inside = 760 × [tex]\frac{4}{2}[/tex]
gas inside = 1560 torr
so partial pressure either side is
partial pressure = 2× 400 = 800 torr
partial pressure = 2× 360 = 720 torr
so we keep vapor pressure here 400 torr
so
final total pressure = 400 + 720
final total pressure is 1120 torr
