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A balloon is filled with 35.0 L of helium in the morning when the temperature is 20.0C. By noon the temperature has risen to 45.0C. What is the new volume of the balloon?



A
2.5L

B
3.5L

C
4.5L

D
5.5L

Respuesta :

joseaaronlara

Answer:

The question to your answer is: V2 = 78.75 l  non if the options given

Explanation:

Data

V1 = 35 l

T1 = 20 °C

T2 = 45°C

V2 = ?

Formula

V1 / T1 = V2 / T2

Clear V2 from the equation

V2 = V1T2/T1

Substitution

V2 = (35)(45) / (20)

V2 = 78.75 l

Answer:

The new volume of the balloon is 78.75 L

Explanation:

Charles's law relates the volume and temperature of an ideal gas, to a constant pressure, therefore we must use that ratio to calculate the final temperature, according to the data provided:

Vinitial = 35 L

Tinitial = 20ºC

Vfinal = ?

Tfinal = 45ºC

Vfinal = (Vinitial x Tfinal)/Tinitial = (35 L x 45ºC)/20ºC = 78.75 L

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