Answer:
Increase of ten yields 10 dB increase
Explanation:
The decibel is a logarithmic scale that shortens a large range of numbers into smaller and more manageable numbers. The decibel is found using:
[tex]dB = 10log(r )[/tex]
Where r represents a ratio of a measured magnitude (pressure or intensity level in sound) to a reference pressure or intensity value. However, in our problem we only need to represent an increase factor of ten:
[tex]dB = 10log(\frac{10}{1} )\\\\dB = 10*1=10 dB[/tex]