Answer:
Joseph is not correct
Each digit from the leftmost digit is ten times the digit before it
Step-by-step explanation:
* Lets explain how to solve the problem
- Any number formed from some digits, each digit has a place value
- Ex: 2,345 this number formed from 4 digits
The place value of 5 is ones ⇒ 5
The place value of 4 is tens ⇒ 40
The place value of 3 is hundreds ⇒ 300
The place value of 2 is thousands ⇒ 2,000
2,345 = 2,000 + 300 + 40 + 5
* Lets check our problem
∵ The number is 9,999,999
- The number formed from 7 digits, the digits have different places value
∴ They couldn't have the same value
∴ Joseph is not correct
∵ The number formed from 7 digits
- The place value of the leftmost digit is millions
- The place value of the digit before the million is hundred thousands
- The place value of the digit before the hundred thousands is
ten thousands
- The place value of the digit ten thousands is thousands
- The place value of the digit before thousands is hundreds
- The place value of the digit before hundreds is tens
- The place value of the digit before tens is ones
∴ 9,999,999 = 9,000,000 + 900,000 + 90,000 + 9,000 + 900
+ 90 + 9
∴ Each digit from the leftmost digit is ten times the digit before it
