Given the sequence below, and that sequence has a domain of n 2 1, find the third
term.
f(n) = 3n+2
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Answer:
Step-by-step explanation:
f(n) = 3n + 2, n ≥ 1
Substitute n = 3:
f(3) = 3(3) + 2 = 9 + 2 = 11
The third term of the sequence is 11 given that that the sequence has a domain of n ≥ 1 and f(n) = 3n + 2. This can be obtained by substituting 3 in the sequence since we have to find the third term.
Given that, the sequence ⇒ f(n) = 3n + 2
Since n ≥ 1, first term will be ⇒ f(1) = 3(1) + 2 = 5
Second term will be f(2) = 3(2) + 2 = 8
Third term will be f(3) = 3(3) + 2 = 11
Thus the sequence is 5, 8, 11, ... and the third term is 11.
Hence the third term of the sequence is 11 given that that the sequence has a domain of n ≥ 1 and f(n) = 3n + 2.
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