Answer:
The required probability is : [tex]\frac{1}{15}[/tex]
Step-by-step explanation:
Three married couples have purchased theater tickets and are seated in a row consisting of just six seats.
First we will check the total arrangements that is 6! ways.
6! = [tex]6\times5\times4\times3\times2\times1=720[/tex]
Jim and Paula can sit at far left in 2 ways and the remaining 4 in 4! ways,.
So, probability will be = [tex]2\times\frac{4!}{6!}[/tex]
= [tex]2\times\frac{24}{720}[/tex]
= [tex]\frac{48}{720}[/tex]
= [tex]\frac{1}{15}[/tex]
