Explanation:
Given that,
Speed with which the bullet is fired, u = 136 m/s
Time, t = 1.3 s
We need to find the displacement of the bullet after 1.3 seconds. It can be calculated using second equation of motion as :
[tex]s=ut+\dfrac{1}{2}at^2[/tex]
Here, a = -g
[tex]s=ut-\dfrac{1}{2}gt^2[/tex]
[tex]s=136\times 1.3-\dfrac{1}{2}\times 9.8\times (1.3)^2[/tex]
s = 168.51 meters
So, the displacement of the bullet after 1.3 seconds is 168.51 meters. Hence, this is the required solution.
