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Cesium atoms are the largest of the naturally occurring elements. They have a diameter of 5.30 1010 m. Calculate the number of cesium atoms that would have to be lined up to give a row of cesium atoms 2.54 cm (1 in.) long.

Respuesta :

Answer:

[tex]N=47,954,528.3 atoms\\N=4.792x10^{7}atoms[/tex]

Explanation:

First we need to match the units of both measures, let's make meters for both of them, so:

[tex]d=5.3x10^{-10} m\\1in=2.54cm=0.0254m[/tex]

Now we need to make a relation between both measures, as we know that the first distance is:

[tex]5.3x10^{-10}m/atom[/tex]

Then:

[tex]N=\frac{0.0254m}{5.3x10^{-10}m/atom} \\\\N=47,954,528.3 atoms\\N=4.792x10^{7}atoms[/tex]

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