Answer:
The answer to your question is:
16.47 g of N2 and 3.52 g of H2
Explanation:
Data
20 g of products were obtain.
Process
AW N2 = 28 g
AW H2 = 2g
MW NH3 = 17 g
N2(g) + 3H2(g) ---> 2NH3(g)
28g 3(2)g 2(17) g
20 g
N2
28 g N2 ------------------- 34 g of NH3
x -------------------- 20 g of NH3
x = 20(28)/34 = 16.47 g of N2
H2 6 g of H2 ------------------- 34 g of NH3
x 20 g of NH3
x = 20(6)/34 = 3.52 g of H2
Total mass = 16.47 g of N2 + 3.52 g of H2 = 19.99 g ≈ 20 g
