Answer:
721.8 Joule per second
Explanation:
L = 33 cm = 0.33 m
A = 55 cm^2 = 0.0055 m^2
Th = 129°C
Tc = 21°C
k = 401 W/mK
The rate of flow of heat is given by the formula
[tex]H =\frac{K A \left ( T_{h}-T_{c} \right )}{L}[/tex]
[tex]H =\frac {401 \times 0.0055 \times \left (129-21\right )}{0.33}[/tex]
H = 721.8 Joule per second
Thus, the rate of flow of heat is given by 721.8 Joule per second.
