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The dimensionless parameter is used frequently in relativity. As y becomes larger and larger than 1, it means relativistic effects are becoming more and more important. What is y if v = 0.932c? A. 0.546 B. 0.362 C. 2.76 D. 3.83 E. 7.61

Respuesta :

Answer:

[tex]\gamma=2.76[/tex]

Explanation:

The relativistic parameter in theory of relativity is given by :

[tex]\gamma=\dfrac{1}{\sqrt{1-\dfrac{v^2}{c^2}}}[/tex]..............(1)

Where

v is the speed

c is the speed of light

Given that, v = 0.932 c

Put the value of v from above equation in equation (1) as :

[tex]\gamma=\dfrac{1}{\sqrt{1-\dfrac{(0.932c)^2}{c^2}}}[/tex]

[tex]\gamma=2.758[/tex]

or

[tex]\gamma=2.76[/tex]

So, the value of the dimensionless parameter is 2.76. Hence, this is the required solution.

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