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The cost (c) to hire a dog trainer is varies directly with the amount of time (h) in hours spent training the dog.
Part A

Write an equation to represent the proportional relationship between c and h using the information given. c =

Part B Sue spent $660 on 12 hours of obedience training for her dog Muffin. Jon wants to use the same dog trainer for his dog Tex, but he only has $440 to spend. How many hours of training can he get for Tex? Explain your reasoning.

Respuesta :

calculista

Answer:

Part A) The proportional equation is [tex]c=55h[/tex]

Part B) 8 hours of training

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form [tex]y/x=k[/tex] or [tex]y=kx[/tex]

Let

c -----> the cost to hire a dog

h ----> the amount of time in hours

The linear equation is equal to

[tex]c=kh[/tex]

Sue spent $660 on 12 hours of obedience training for her dog Muffin

Find the value of k (constant of proportionality)

[tex]k=y/x[/tex]

substitute the values

[tex]k=660/12=55[/tex]

therefore

The linear equation is

[tex]c=55h[/tex]

For [tex]c=\$440[/tex]

Find the value of h

substitute in the equation and solve for h

[tex]440=55h[/tex]

[tex]h=440/55=8\ hours[/tex]

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