Respuesta :
The intensity of X-ray beam of second exposure made at 100 cm SID is 20 mR.
Solution:
By using inverse square law formula, intensity of X-Ray beam made at different distances can be found.
[tex]\frac{I_{1}}{I_{2}}=\left(\frac{D_{2}}{D_{1}}\right)^{2}[/tex]
Where [tex]I_1[/tex] is the intensity of first exposure of X-ray-beam.
[tex]I_2[/tex] is the intensity of second exposure of X-ray beam.
[tex]D_1[/tex] is the distance at which first exposure is made.
[tex]D_2[/tex] is the distance at which second exposure is made.
[tex]\begin{array}{l}{\frac{I_{1}}{I_{2}}=\left(\frac{100}{200}\right)^{2}} \\\\ {\frac{5}{I_{2}}=\frac{1}{4}} \\\\ \bold{{I_{2}=20\ \mathrm{mR}}\end{array}}[/tex]
