Respuesta :
Answer:
The answer is 2.3 eV
Explanation:
As energy should be conserved, we have to understand that the energy gap between the ground state and excited state is equal to the energy of the emitted photons.
The wavelength of the emitter photons is
[tex]\lambda = 539\ nm = 539 \times 10^{-9}\ m[/tex],
then their energy is
[tex]E = \frac{h c}{\lambda} = 36.855 \times 10^{-20}\ J[/tex]
where h is the Planck constant,
[tex]h = 6.626 \times 10^{-34}\ Js[/tex]
and c is the speed of light,
[tex]c = 2.998 \times 10^{8}\ m/s[/tex].
If we want our answer in electron-volts instead of joules...
[tex]1 J = 6.242 \times 10^{18}\ eV[/tex]
then
[tex]E = 36.855 \times 10^{-20} J = 2.3\ eV[/tex].
We have that for the Question "The laser pointer emits light because electrons in the material are excited (by a battery) from their ground state to an upper excited state. When the electrons return to the ground state, they lose the excess energy in the form of 539-nm photons. What is the energy gap between the ground state and excited state in the laser material?" it can be said that the energy gap between the ground state and excited state in the laser material is
[tex]E=2.3ev[/tex]
From the question we are told
The laser pointer emits light because electrons in the material are excited (by a battery) from their ground state to an upper excited state. When the electrons return to the ground state, they lose the excess energy in the form of 539-nm photons. What is the energy gap between the ground state and excited state in the laser material?
Generally the equation for the Energy is mathematically given as
[tex]E=\frac{h*c}{\lambda}\\\\E=\frac{6*6*10^{-34}*3*10^8}{539*10^{-9}}\\\\E=36.855*10^{-20}[/tex]
[tex]E=2.3ev[/tex]
Therefore
the energy gap between the ground state and excited state in the laser material is
[tex]E=2.3ev[/tex]
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