Answer: 0.3173
Step-by-step explanation:
Given : A machine that cuts corks for wine bottles operates in such a way that the distribution of the diameter of the corks produced is well approximated by a normal distribution with
[tex]\mu=4\ cm[/tex] and [tex]\sigma=0.2\ cm[/tex]
The specifications call for corks with diameters between 3.8 and 4.2 cm.
Let x be the random variable that represents the the diameter of the corks.
Using formula [tex]z=\dfrac{x-\mu}{\sigma}[/tex], the z-score corresponding to x= 3.8 will be :_
[tex]z=\dfrac{3.8-4}{0.2}=1[/tex]
z-score corresponding to x= 4.2 will be :_
[tex]z=\dfrac{4.2-4}{0.2}=1[/tex]
Now, by using the standard normal distribution table for z, we have
[tex]\text{P value}=P(-1<z<1)=2P(z<1)-1\\\\=2(0.8413447)-1\\\\=0.6826894\approx0.6827[/tex]
∴The proportion of corks produced by this machine are meeting the specifications=0.6827
∴The proportion of corks produced by this machine are defective = [tex]1-0.6827=0.3173[/tex]