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If you drop a 50 gram piece of metal that has a temperature of 110°Celsius into 1000 grams of water at 25°Celsius, what best describes what would occur?

A.) The water will quickly reach the boiling point.
B.) The water’s temperature will stay the same, but the metal will cool down.
C.) The water’s temperature will increase, and the metal will stay constant.
D.)The water and the metal’s temperature will reach the same temperature.

Respuesta :

If you drop a 50 gram piece of metal that has a temperature of 110°Celsius into 1000 grams of water at 25°Celsius, D.)The water and the metal’s temperature will reach the same temperature. In any system undergoing heat transfer, the objects involved will eventually reach the same temperature, signifying thermal equilibrium.

Answer:

D.)The water and the metal’s temperature will reach the same temperature.

Explanation:

As we know that heat is a dynamic energy which will flow from high temperature to low temperature.

So here we know that 50 g metal piece at 110 degree Celsius is dropped into the water at 25 degree Celsius. Since metal is at higher temperature so here the heat will flow from metal to the water and this will continue till the temperature of these two bodies will become equal.

So here the final temperature of metal and the water will be same at thermal equilibrium.

So here correct answer will be

D.)The water and the metal’s temperature will reach the same temperature.

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