The resting heart rates for 80 women aged 46–55 in a simple random sample are normally distributed, with a mean of 71 beats per minute and a standard deviation of 6 beats per minute. Assuming a 90% confidence level, what is the margin of error for the population mean?

0.66
1.10
1.31
1.73

The margin of error can be calculated using the formula:

1. ME = critical value * standard deviation / sqrt(sample size)
2. ME = critical value * standard error

Since we are given the standard deviation and the sample size, we can use equation 1. The critical value is always fixed and can be determined using a t or z graph. For 90% confidence level, the CV is 1.645.

ME = 1.645(6)/sqrt80 = 1.1

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thesmiths0987654321 thesmiths0987654321 · Answer 2 · 2020-06-01T22:29:00+02:00

thesmiths0987654321 thesmiths0987654321

01-06-2020

Answer:

b. 1.10

Step-by-step explanation:

right on edge

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The resting heart rates for 80 women aged 46–55 in a simple random sample are normally distributed, with a mean of 71 beats per minute and a standard deviation of 6 beats per minute. Assuming a 90% confidence level, what is the margin of error for the population mean? 0.66 1.10 1.31 1.73

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The resting heart rates for 80 women aged 46–55 in a simple random sample are normally distributed, with a mean of 71 beats per minute and a standard deviation of 6 beats per minute. Assuming a 90% confidence level, what is the margin of error for the population mean?

0.66
1.10
1.31
1.73