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At a high school, the probability that a student takes a science class and a history class is 0.48. The probability that a student takes a science class is 0.82, and the probability that the student takes a history class is 0.64. What is the probability (rounded to the nearest hundredth) that a student takes a history class given that the student is taking a science class?
A)0.39
B)0.75
C)0.30
D)0.59

Respuesta :

Solutions 

Probability: number of favourable outcomes
                   __________________________

                   total number of possible outcomes

In general, the total number of possible outcomes can be determined by multiplying the number of possible outcomes for each event. 

P(A|B)= [tex] \frac{P(A,B)}{P(B)} [/tex] 

P(A|B) ⇒ P(taking history | taking science) , Therefore A corresponds to taking history, B corresponds to taking science. 

P(A,B) will be the probability that a student is taking both of the subjects. 

P(B) is the probability that a student is taking the subject science                       (regardless of whether he/she takes history or not)

Now to solve the problem you plug in the given numbers. 

0.48 ÷ 0.82

0.48 is the Probability of (A,B) and 0.82 is the Probability of (B) 

= 0.58537 

Rounded to 0.59 

Answer = (D) 

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