Answer:
1568m
Explanation:
An airplane on a runway accelerates at 4.0 meters/second2 for 28.0 seconds before takeoff. How far does the plane travel on the runway before takeoff?
Motion is he change in position of an object with respect to time.
velocity:is the displacement change with respect to time
distance is
From newton's equation of motion
S=ut+1/2at^2
We assume that the airplane is starting from rest
at rest u ,initial velocity becomes 0
a, acceleration 4m/s^2
t, time=28secs
we superpose into the equation, we have
S=0*4+0.5*4*28^2
S=1568m
