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Consider a product with three components in​ series, with reliabilities of​ 0.90, 0.80, and 0.99 for components​ A, B, and​ C, respectively.​ Furthermore, component B uses a backup that also has a reliability of 0.80. What is the reliability of the​ system?

Respuesta :

Answer:0.853

Explanation:

Given

Reliability of A is 0.90

Reliability of B is 0.80

Reliability of C is 0.99

B has a backup with reliability of 0.8

i.e. B has a component in parallel to it.

A,B& C is series.

B actual reliability is

[tex]R_b=1-\left ( 1-0.8\right )\left ( 1-0.8\right )[/tex]

[tex]R_b=0.96[/tex]

Thus [tex]R_{net}[/tex] is given by

[tex]R_{net}=R_A\times R_B\times R_C[/tex]

[tex]R_{net}=0.9\times 0.96\times 0.99[/tex]

[tex]R_{net}=0.8553[/tex]

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