Answer:
[tex]7.2878\times10^{16} m[/tex]
Explanation:
Time elapsed on Earth [tex]d_{t}[/tex]= 12 years
Time elapsed on board the ship[tex]d_{t_o}[/tex] = 9.2 years
now r= [tex]\frac{d_{t} }{d_t_o}[/tex]= 12/9.2= 1.3043
[tex]v= c \sqrt{1-\frac{1}{r^2}}[/tex]
[tex]v= 3\times10^8 \sqrt{1-\frac{1}{1.3043^2}}[/tex]
v= [tex]1.9258\times10^8[/tex]
therefore distance L= [tex]d_{t}\times v[/tex]
putting value we get
=[tex]12\times\times1.9258\times10^8 [/tex]
=[tex]12\times\times365\times24\times3600\times1.9258\times10^8 [/tex]
= [tex]7.2878\times10^{16} m[/tex]
