Answer:
The vertices are at (3, 0) and (-3, 0).
The foci are at (5, 0) and (-5, 0).
Step-by-step explanation:
Compare given equation x^2/9 - y^2/16 = 1
against standard hyperbola form (x - h)^2 / a^2 - (y - k)^2 / b^2 = 1,
the hyperbola opens left and right with its center (h, k) at (0, 0).
a^2 = 9 so a = +/-3
The vertices are at (3, 0) and (-3, 0).
a^2 + b^2 = c^2 where c is 2x distance between foci.
9 + 16 = c^2
c = +/-5
The foci are at (5, 0) and (-5, 0).
