Explanation:
Given that,
Speed = 32.5 m/s
Frequency = 212 Hz
We need to calculate the frequency
When the train approaching then from Doppler effect
[tex]f'=\dfrac{V_{0}}{V-V_{s}}f[/tex]
Put the value into the formula
[tex]f'=\dfrac{344}{344-32.5}\times f[/tex]
[tex]f'=234.11\ Hz[/tex]
The frequency of the approaching train horn is 234.11 Hz.
We need to calculate the frequency when the train away from the person
Again using Doppler effect
[tex]f''=\dfrac{v}{v+v_{s}}f[/tex]
[tex]f''=\dfrac{344}{344+32.5}\times212[/tex]
[tex]f''=193.7\ Hz[/tex]
The frequency of the receding train is 193.7 Hz.
Hence, This is required solution.