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An elderly sailor is shipwrecked on a desert island but manages to save his eyeglasses. The lens for one eye has a power of +1.17 diopters, and the other lens has a power of +9.47 diopters. What is the magnifying power of the telescope he can construct with these lenses? Tries 0/20 How far apart are the lenses when the telescope is adjusted for minimum eyestrain?

Respuesta :

Answer:

Explanation:

Focal length of first lens =100/1.17 =85.47 cm

Focal length of second lens = 100/9.47 = 10.56 cm

The first lens will be used as object lens , so F (o) = 85.47 cm.

The second lens will be used as eye lens , so F(e) = 10.56cm.

Magnifying power = F(o)/F(e) = 85.47/10.56 =  8.09.

Distance between two lenses = F(o) + F(e) = 85.47 + 10.56 = 96.03 cm.

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