Consider a uniform distribution from aequals=44 to bequals=2828. ​(a) Find the probability that x lies between 1111 and 2424. ​(b) Find the probability that x lies between 99 and 2222. ​(c) Find the probability that x lies between 77 and 1919. ​(d) Find the probability that x lies between 1010 and 2323.

Respuesta :

Answer with explanation:

Given : The interval for a uniform distribution : (4, 28)

The density function for the uniform distribution will be :-

[tex]f(x)=\dfrac{1}{28-4}=\dfrac{1}{24}[/tex]

(a) Required interval : (11,24) = [tex]24-11=13[/tex]

Now, the probability that x lies between 11 and 24 is given by :-

[tex]=\text{(Required interval)} \cdot\ f(x)=\dfrac{13}{24}[/tex]

(b) Required interval : (9,22) = [tex]22-9=13[/tex]

Now, the probability that x lies between 9 and 22 is given by :-

[tex]=\dfrac{13}{24}[/tex]

(c) Required interval : (7,19) = [tex]19-7=12[/tex]

Now, the probability that x lies between 9 and 22 is given by :-

[tex]=\dfrac{12}{24}=0.5[/tex]

(d)Required interval : (10,23) = [tex]23-10[/tex]

Now, the probability that x lies between 9 and 22 is given by :-

[tex]=\dfrac{13}{24}[/tex]