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A biconvex lens is one in which both surfaces of the lens bulge outwards. Suppose you had a biconvex lens with radii of curvature with magnitudes of R 1= 10cm and R 2 = 15cm. The lens is made of glass with index of refraction n=1.5. We will employ the convention that R 1 refers to the radius of curvature through wich light will enter the lens, and R 2 refers to the radius of curvature from which the light will exit the lens.

Is this lens converging or diverging?

What is the focal length of this lens in air?

Respuesta :

Answer:

The focal length is 12 cm and the lens is converging.

Explanation:

Given that,

Radius, R ₁=10 cm

R₂ =15 cm

Index of refraction n= 1.5

We need to calculate the focal length of the lens

Using formula of focal length

[tex]\dfrac{1}{f}=(n-1)(\dfrac{1}{R_{1}}+\dfrac{1}{R_{2}})[/tex]

Put the value into the formula

[tex]\dfrac{1}{f}=(1.5-1)(\dfrac{1}{10}+\dfrac{1}{15})[/tex]

[tex]\dfrac{1}{f}=0.0833[/tex]

[tex]f =12\ cm[/tex]

The focal length of the lens is positive so the lens is converging.

Hence, The focal length is 12 cm and the lens is converging.

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