Answer: The mass of water that must be reacted is 56.28 grams.
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] ....(1)
Given mass of oxygen = 50 g
Molar mass of oxygen = 32.00 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of oxygen}=\frac{50g}{32g/mol}=1.5625mol[/tex]
For the given chemical equation:
[tex]2H_2O\rightarrow 2H_2+O_2[/tex]
By Stoichiometry of the reaction:
1 mole of oxygen is produced when 2 moles of water is reacted.
So, 1.5625 moles of oxygen is produced when = [tex]\frac{2}{1}\times 1.5625=3.125mol[/tex] of water is reacted.
To calculate the mass of water, we use equation 1:
Moles of water = 3.125 moles
Molar mass of water = 18.01 g/mol
Putting values in equation 1, we get:
[tex]3.125mol=\frac{\text{Mass of water}}{18.01g/mol}\\\\\text{Mass of water}=56.28g[/tex]
Hence, the mass of water that must be reacted is 56.28 grams.
