Answer:
Equal df
Step-by-step explanation:
Given that a chi square test for goodness of fit is used to examine the distribution of individuals across three categories,
Hence degree of freedom = 3-1 =2
Similarly for a chi-square test for independence is used to examine the distribution of individuals in a 2×3 matrix of categories.
Here degree of freedom = (r-1)(c-1) where r = no of rows and c =no of columns
= (2-1)(3-1) = 2
Thus we find both have equal degrees of freedom.