Explanation:
It is given that,
Mass of the block, m = 0.253 kg
Force constant, k = 4825 N/m
Compression in the spring, x = 0.097 m
After the block is released from rest, it travels upward and then leaves the spring. Using the conservation of energy as :
[tex]\dfrac{1}{2}kx^2=mgh[/tex]
[tex]h=\dfrac{kx^2}{2mg}[/tex]
[tex]h=\dfrac{4825\times (0.097)^2}{2\times 0.253 \times 9.8}[/tex]
h = 9.15 m
So, the block will go to the maximum height of 9.15 meters. Hence, this is the required solution.
