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A 100 g ice cube having an initial temperature of 0°C is put into an insulated cup containing 200 g of water. After a long time, all the ice is melted and the remaining water is at 0°C. Assuming no heat flows into or out of the cup, what was the initial temperature of the water?

Respuesta :

Answer:

39.8 °C

Explanation:

m = mass of the ice = 100 g

L = latent heat of fusion of ice = 334 Jg⁻¹

M = mass of water = 200 g

[tex]c_{w}[/tex] = specific heat of water = 4.2 Jg⁻¹°C⁻¹

[tex]T_{wi}[/tex] = initial temperature of water = ?

[tex]T_{wf}[/tex] = final temperature of water = 0 °C

Using conservation of heat

Heat gained by ice = heat lost by water

m L = M [tex]c_{w}[/tex] ([tex]T_{wi}[/tex] - [tex]T_{wf}[/tex] )

(100) (334) = (200) (4.2)  ([tex]T_{wi}[/tex] - 0 )

[tex]T_{wi}[/tex] = 39.8 °C  

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