Answer: Option (B) is the correct answer.
Explanation:
A molecules that will have more number of hydrogen bonding will has highest boiling point because to break the hydrogen bonds high heat needs to be provided.
So, in the molecule [tex]HOCH_{2}CH_{2}OH[/tex] there is presence of two alcoholic groups. Hence, it will have strongest hydrogen bonding as compared to the rest of molecules.
In the molecule [tex]ClCH_{2}CH_{2}OH[/tex] there will be hydrogen bonding and dipole-dipole interactions. Hence, it boiling point will be slightly less than [tex]HOCH_{2}CH_{2}OH[/tex].
In the molecule [tex]CH_{3}CH_{2}OH[/tex], there will be only hydrogen bonding. Hence, its boiling point is less than [tex]ClCH_{2}CH_{2}OH[/tex].
In the molecule [tex]CH_{3}CH_{2}Cl[/tex], there is no hydrogen bonding but there will be only dipole-dipole interactions. Hence, its boiling point will be the least.
Therefore, we can conclude that increasing order of boiling point will be as follows.
[tex]CH_{3}CH_{2}Cl[/tex] < [tex]CH_{3}CH_{2}OH[/tex] < [tex]ClCH_{2}CH_{2}OH[/tex] < [tex]HOCH_{2}CH_{2}OH[/tex]
The arrangement of the Substances in order of increasing boiling point is;
CH3CH2Cl < CH3CH2OH < ClCH2CH2OH < HOCH2CH2OH
The order in which the substances are arrangement is on the basis of the bonds present.
By convention, substances with dipole-dipole bonds have lower boiling point compared to compounds with hydrogen bonding.
As such, the order of arrangement in terms of boiling point is;
CH3CH2Cl < CH3CH2OH < ClCH2CH2OH < HOCH2CH2OH.
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