Respuesta :
Answer:
[tex]y=32000(1+0.08)^x[/tex]
Step-by-step explanation:
Exponential growth function is [tex]y=a(1+r)^x[/tex]
Where 'a' is the initial population
r is the rate of growth and x is the time period in years
a steady population of 32,000. So initial population is 32,000
an increase of 8% per year. the rate of increase is 8% that is 0.08
a= 32000 and r= 0.08
Plug in all the values in the general equation
[tex]y=a(1+r)^x[/tex]
[tex]y=32000(1+0.08)^x[/tex]
[tex]y=32000(1+0.08)^x[/tex]
The equation that can be used to predict, y the number of people living in the town after x years is [tex]y = 32000(1.08)^x[/tex]. The correct option is A).
Given :
Steady population of 32000.
After 1 year and an increase of 8% per year, the population is 34560.
We know that the exponential growth function is given by,
[tex]y= a(1+r)^x[/tex] ---- (1)
Where, 'a' is the initial population, 'r' is the rate of growth and 'x' is the time period in years.
Now put the values of x, r and a in equation (1) we get,
[tex]y = 32000\times (1+0.08)^x[/tex]
[tex]y = 32000(1.08)^x[/tex]
Therefore the equation that can be used to predict, y the number of people living in the town after x years is [tex]y = 32000(1.08)^x[/tex]. The correct option is A).
For more information, refer the link given below
https://brainly.com/question/3127939
