A fair spinner is numbered 1 to 8. It is spun 768
times. How many times would you expect to get a
square number?

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hoangpm04 hoangpm04 · Answer 1 · 2019-08-15T13:06:13+02:00

Answer:

NOT BE EXACTLY 192 times but it would be NEAR 192 times.

Step-by-step explanation:

A square number is a number that multiplied by itself like 4 because 4 = 2*2

The total square numbers from 1 to 8 would be: 1 and 4 (2 total)

So the probability of roling either 1 or 4 in 1 time would be:

probability of rolling 1 or 4/ total outcomes probability

= 2/8 = 1/4 or 25%

So if it is spun 768 times, the total times that would show either 1 or 4 would be:

1/4 * 768 = 192 times.

So the possible of total times getting an 1 or 4 may NOT BE EXACTLY 192 times but it would be NEAR 192 times.

Hope this help you :3

Аноним Аноним · Answer 2 · 2019-08-15T13:27:26+02:00

Answer:

192.

Step-by-step explanation:

The square numbers between 1 and 8 are 1 and 4 so there are 2 of them.

So the probability of getting a square number on 1 throw = 2/8 = 1/4.

So on 768 throws you expect to get 1/4 * 768 = 192.

In practice you might not get 192 but as it's a fair spinner you would get close to 192.

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